$\forall$$A$:Type, ${\it eq}$:EqDecider($A$), $B$:($A$$\rightarrow$Type), $g$:$x$:$A$ fp$\rightarrow$ $B$($x$). fpf{-}normalize(${\it eq}$;$g$) $\in$ $x$:$A$ fp$\rightarrow$ $B$($x$)